f(x)=x+4(2x+1)8x^2+4

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Solution for f(x)=x+4(2x+1)8x^2+4 equation:


Simplifying
f(x) = x + 4(2x + 1) * 8x2 + 4

Multiply f * x
fx = x + 4(2x + 1) * 8x2 + 4

Reorder the terms:
fx = x + 4(1 + 2x) * 8x2 + 4

Reorder the terms for easier multiplication:
fx = x + 4 * 8x2(1 + 2x) + 4

Multiply 4 * 8
fx = x + 32x2(1 + 2x) + 4
fx = x + (1 * 32x2 + 2x * 32x2) + 4
fx = x + (32x2 + 64x3) + 4

Reorder the terms:
fx = 4 + x + 32x2 + 64x3

Solving
fx = 4 + x + 32x2 + 64x3

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.
f = 4x-1 + 1 + 32x + 64x2

Simplifying
f = 4x-1 + 1 + 32x + 64x2

Reorder the terms:
f = 1 + 4x-1 + 32x + 64x2

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